27x^2+26x-1=0

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Solution for 27x^2+26x-1=0 equation:



27x^2+26x-1=0
a = 27; b = 26; c = -1;
Δ = b2-4ac
Δ = 262-4·27·(-1)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-28}{2*27}=\frac{-54}{54} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+28}{2*27}=\frac{2}{54} =1/27 $

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